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Asked by shahnshahdhavaniya | 29 Aug, 2021, 10:31: AM
Given Network of resistors is redrawn in Step-1 as shown in figure so that it is easy to understand
the parallel-series combinations. As we see in Step-1 , top three resistors of equal resistance R are in parallel.

Hence equivalent resistance R/3 of three equal resistors is replacing the three resistors in step-2 of figure.

From step-2 , we see that if resitance is measured across A and B ,
then we have series combination of R/3 and  R is in parallel to resistance R  as shown in step-3.

Hence Effective resistance Reff = [ (R/3) + R ] || R  = (4/3)R || R =   [ (4/3)R × R ] / [ (4/3)R + R ]   = (4/7) R

If effective resistance (4/7)R = 1 Ω , then resistance R of  each resistors is given as  R = (7/4) Ω
Answered by Thiyagarajan K | 30 Aug, 2021, 06:45: PM

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