CBSE Class 12-science Answered

The circuit is redrawn and shown above. We see that resistors R₂, R₃ and R₄ are in parallel .

Equivalenet resistance of R₂, R₃ and R₄ is

Hence, Equivalent resistance of circuit is ( 6 + 4 ) Ω = 10 Ω .

Current drawn from battery = 10 V / 10 Ω = 1 A

Current through resistor R₁ = 1 A ;

Potential difference across R₁ = ( 1 A × 4 Ω ) = 4 V

Potential difference across A and B = ( 10 - 4 ) V = 6 V

Current through R₂  = 6 V / 15 Ω = 0.4 A

Current through R₃ = 0.4 A

Current through R₄ = 6 V / 30 Ω = 0.2 A .