Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

93219 24448 / 89292 63204

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

81783 72169
OR

Chat with us on WhatsApp

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

Home / Doubts and Solutions/JEE/Physics

Solve all the three paragraph question in detail

qsnImg
Asked by sarveshvibrantacademy 4th May 2019, 10:38 AM
Answered by Expert
Answer:
For the refraction at spherical surface, we have     begin mathsize 12px style fraction numerator mu subscript 1 over denominator negative x end fraction plus mu subscript 2 over v space equals space fraction numerator mu subscript 2 minus mu subscript 1 over denominator R end fraction space space o r space fraction numerator begin display style mu subscript 2 end style over denominator begin display style v end style end fraction space equals space fraction numerator begin display style mu subscript 2 minus mu subscript 1 end style over denominator begin display style R end style end fraction plus space fraction numerator begin display style mu subscript 1 end style over denominator begin display style x end style end fraction end style .............................(1)
Qn. (25)
(A) as per eqn.(1),  since x and R are positive, if μ2 > μ1 , v is always positive. Hence real image is formed always if μ2 > μ1.
 
(B) false as per the explanation given above for (A)

(C) if μ2 < μ1 first term of RHS of eqn.(1) is negative. Hence if μ2 < μ1 and ( μ1 - μ2)/R > μ1/x  v will be negative. 
In such a case, even with convex nature, v is negative and real image wil not be formed
 
-----------------------------------------------
Qn.(26)
(A) as discussed in qn.(25) if μ2 < μ1 and ( μ1 - μ2)/R > μ1/x  v will be negative. if v is negative virtual mage is formed
 
if the above condition is rewritten, we have [ x > μ1 R/ ( μ1 - μ2) ] ..............(2)
Virtual image is formed only for the position of x that satisfies eqn.(2), 
 
-----------------------------
Qn.27
for a concave spherical surface, we have begin mathsize 12px style fraction numerator mu subscript 1 over denominator negative x end fraction space plus space mu subscript 2 over v space equals space fraction numerator mu subscript 2 minus mu subscript 1 over denominator negative R end fraction space space space o r space space fraction numerator begin display style mu subscript 2 end style over denominator begin display style v end style end fraction space equals space fraction numerator begin display style mu subscript 1 minus mu subscript 2 end style over denominator begin display style R end style end fraction space space plus fraction numerator begin display style mu subscript 1 end style over denominator begin display style x end style end fraction space end style ...................(3)
(A) if μ2 > μ1 , first term of RHS of eqn.(3) is negative. Hence if x > [ μ1 R /( μ2 - μ1) ], v is negative  and
virtual image is formed for the position x satisfying this condition
 
(B) if μ2 < μ1 , RHS of eqn.(3) is positive, hence v is positive. Virtual image will not be formed in such a case
 
(C) as explained in (B), if μ2 < μ1, real image is formed for any value of x
Answered by Expert 6th May 2019, 10:19 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Report an issue
Tags: refraction
Previous Question
Next Question
Your answer has been posted successfully!

Free related questions

why dos the sun appear oval at sunset and surise but appears circular at noon
21st January 2021, 9:07 AM
What is Refraction of light
4th February 2021, 7:45 PM
when refraction does not cause when incident ray is normal to a interface
2nd March 2021, 9:52 PM
Refraction of light class 10 simple defination
12th April 2021, 12:54 PM
(a) Choose the correct statement with respect to Refraction of light [1] 1. The colour always changes when light enters from one optical medium to another. 2. Absorption of light when it strikes the surface of a medium is refraction. 3. Speed of light changes when it enters from one optical medium to another of different optical density. 4. Speed of light does not change when it enters from one optical medium to another of different optical density.
26th August 2021, 7:09 PM
RELATED STUDY RESOURCES :
JEE QUESTION ANSWERS

Browse free questions and answers by Chapters

Trending Tags

balancing chemical equations cube acceleration cubic identities GST digestion hcf pythagoras theorem original fraction gravitational force

Latest Questions

CBSE X Biology
What is enzyme  
Asked by Sureshgowdayd548 28th October 2020, 10:50 PM
JEE Main Mathematics
The following pseudocode is executed using the “Paragraph words” dataset. At the end of the execution, CountB captures the number of verbs with letter count less than the average letter count of verbs. But the pseudocode may have mistakes in one or more lines. Identify all such lines (if any). It is a Multiple Select Question (MSQ).  Error in Line 4  Error in Line 8  Error in Line 11  Error at Line 12  Error in Line 17  Error at Line 18  Error in Line 21 The following pseudocode is executed using the “Words” table. What will be the value of A at the end of the execution?
Asked by amaladelsingh 28th October 2020, 10:24 PM
CBSE X Biology
I want a brief clarity on Taxonomy
Asked by reenacharan2008 28th October 2020, 9:11 PM

Chat with us on WhatsApp