Request a call back

Join NOW to get access to exclusive study material for best results

JEE Class main Answered

solve
question image
Asked by sarveshvibrantacademy | 18 May, 2019, 11:01: AM
answered-by-expert Expert Answer
Refraction at spherical surface , we have  begin mathsize 12px style mu over v minus 1 over u space equals space fraction numerator mu minus 1 over denominator R end fraction end style .............................(1)
where μ is refractive index, v is image distance and R is radius of curvature.
 
for the spherical surface above AB,  (1.6/v) + (1/2) = (0.6/1)   or v = 16 m ........................(2)
 
for the spherical surface below AB,  (2/v) + (1/2) = (1/1)    or  v = 4 m .........................(3)
 
From eqn.(2) and eqn.(3),  Image separation distance = 16-4 = 12 m
Answered by Thiyagarajan K | 18 May, 2019, 03:26: PM
JEE main - Physics
Asked by arivaryakashyap | 23 Apr, 2024, 10:40: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by ksahu8511 | 19 Apr, 2024, 11:55: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by mohammedimroz | 13 Apr, 2024, 09:48: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by medhamahesh007 | 02 Apr, 2024, 11:11: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by gundlasumathi93 | 31 Mar, 2024, 02:13: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by chhayasharma9494 | 31 Mar, 2024, 12:47: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by Machinenineha | 27 Mar, 2024, 05:28: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by nandichandi33 | 24 Mar, 2024, 09:21: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×