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Asked by mahesh joshi 4th January 2012, 11:17 PM
Answered by Expert

Carbonate (CO32- ) is the conjugate base of the weak acid HCO3-  so when CO32- is placed in water, it reacts to some extent with the water and takes away a proton from it and produces HCO3- and OH-. Now we know that OH- is a strong base so the solution of sodium carbonate becomes alkaline.

The reaction is as follows:

CO32- + H2O ----> HCO3- + OH-

Answered by Expert 5th January 2012, 9:40 AM
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