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CBSE Class 10 Answered

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Asked by arindeep.singh | 17 Sep, 2020, 11:19: AM
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Given: Three points A(a, 1), B(1, -1) and C(11, 4) are collinear
Therefore, area of a triangle formed by these three points will be zero
 
1 half open square brackets straight a open parentheses negative 1 minus 4 close parentheses plus 1 open parentheses 4 minus 1 close parentheses plus 11 open parentheses 1 plus 1 close parentheses close square brackets equals 0 minus 5 straight a plus 3 plus 22 equals 0 5 straight a equals 25 straight a equals 5
Answered by Renu Varma | 17 Sep, 2020, 01:49: PM

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CBSE 10 - Maths
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Asked by arindeep.singh | 17 Sep, 2020, 11:19: AM
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Asked by priyalpathak06 | 05 May, 2019, 11:55: PM
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