CBSE Class 8 Answered
quadrilateral question
Asked by borahbhairabjyoti60 | 16 Mar, 2019, 02:59: PM
Expert Answer
In ΔAOB , OA = OB (radii of circle), Hence ΔAOB is isoceless triangle.hence 
OAB = OBA ................(1)
OAB = OBA ................(1)Given : AOB = 60° . Hence due to (1), OAB = OBA = 60° . Hence ΔAOB is equilateral triangle.
AOB = 60° . Hence due to (1), OAB = OBA = 60° . Hence ΔAOB is equilateral triangle.Given : BOC = 60°. Hence similar to ΔAOB, ΔBOC also equilateral triangle.
BOC = 60°. Hence similar to ΔAOB, ΔBOC also equilateral triangle.ABO = BOC =60°, also ABO and BOC are alternate angles. hence AB is parallel to OCCBO = BOA = 60°, also CBO and BAC are alternate angles. hence OA is parallel to CBalso OA, AB, BC and OC are sides of equilateral triangles and both equilaeral triangles are congruent.
Hence all sides are equal. Hence quadrilateral OABC is rhombus.
length of diagonal OB is same as sides of rhombus, because OB is radius of circle and each side of rhombus is same as radius of circle.
Answered by Thiyagarajan K | 16 Mar, 2019, 04:58: PM
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