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CBSE Class 12-science Answered

Q) The electric field in a region is given by rightwards arrow for E of equals fraction numerator a left parenthesis x i with overbrace on top plus y j with overbrace on top plus z k with overbrace on top right parenthesis over denominator left parenthesis x squared plus y squared plus z squared right parenthesis to the power of begin display style 3 over 2 end style end exponent end fraction space. p r o v e space t h a t space t h e space f l u x space t h r o u g h space t h e space s u r f a c e space o f space a space c a s e space o f space s i d e space l e n g t h space l space c e n t e r e d space a t space t h e space o r i g i n space i s space 4 πa.
Asked by araima2001 | 07 Jun, 2017, 03:43: PM
answered-by-expert Expert Answer
Dear araima2001@yahoo.com

Thanks for asking us a question in Ask the Expert/Homework Help section of TopperLearning.com.

The electric flux through the given area is given by the following relation:

Electric flux is proportional to the number of electric field lines going through a normally perpendicular surface. If the electric field is uniform, the electric flux passing through a surface of vector area S is

F=E.S

Where, where E is the electric field (V/m), E is its magnitude, S is the area of the surface.

Due to the obscurity of the geometry (shape) of the given surface, we are not able to deduce the area of the surface which is required to calculate the flux.

 

Regards

Topperlearning Team.
Answered by Abhijeet Mishra | 09 Jun, 2017, 10:26: AM

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