ICSE Class 10 Answered
Q.
Asked by Int123 | 31 May, 2016, 09:41: PM
Expert Answer
2C2H6 +7O2 → 4CO2 +6H2O
2 V 7 V 4 V
Now from equation, 2V of ethane reacts with = 7 V of oxygen
So, 600cc of ethane reacts with= 600 X 7/2 = 2100cc
Hence, unused O2 is = 2500 - 2100 = 400 cc
From 2V of ethane = 4 V of CO2 is produced
So, 600cc of ethane will produce = 4 X 600/2 =1200cc CO2
Answered by Vaibhav Chavan | 01 Jun, 2016, 10:38: AM
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