ICSE Class 10 Answered
calculate the ratio between the volume of gaseous products formed on catalytic oxidation of 500ml of ammonia according to equation
Asked by kundus458 | 07 Feb, 2024, 08:55: AM
Expert Answer
Dear Student,
According to Gay Lussac's Law, "The ratio between the volumes of the reactant gases and the gaseous products can be expressed in simple whole numbers,"
4NH3 + 5O2 → 4NO + 6H2O
4 v : 5v → 4v : 6v
The raio will remain the same whatever will be the volume taken of the reactants.
Hence,
since 4v of ammonia produces 4v of NO and 6v of water
so, 500 mL of ammonia will produce 500 mL of NO and 750 mL of water
The ratio of the products will be:
500 mL : 750 mL
i.e. 4v : 6v or 2v : 3v
Answered by | 11 Feb, 2024, 01:09: PM
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