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# Prove

Asked by 31st August 2008, 6:44 PM

we know that (1+w+w2) = 0 and w3 =1

x2 + y2 +z2 = a2+b2+2ab+a2w2+b2w4+2abw3+a2w4+b2w2+2abw3

now putting w3=1 and w4= w

x2 + y2 +z2 = a2 (1+w+w2)+b2 (1+w+w2)+6ab= 6ab

Answered by Expert 6th September 2008, 6:32 PM
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