quad eq. 3

Asked by varunsinghal2011 | 9th May, 2010, 03:45: PM

Expert Answer:

a > b > c

a -b > 0 > c - b

0 > c - b + a - a  - b + b

0 > (c - 2b + a) - a + b

since b < a

-a + b < 0  .............. (1)

Hence,  in 0 > (c - 2b + a) - a + b,

0 > (c - 2b + a) is true, since the other part -a + b is shown zero as per (1).

Similarly second inequality can be proved.

Regards,

Team,

TopperLearning.

 

Answered by  | 12th May, 2010, 07:15: PM

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