quad eq. 3
Asked by varunsinghal2011 | 9th May, 2010, 03:45: PM
a > b > c
a -b > 0 > c - b
0 > c - b + a - a - b + b
0 > (c - 2b + a) - a + b
since b < a
-a + b < 0 .............. (1)
Hence, in 0 > (c - 2b + a) - a + b,
0 > (c - 2b + a) is true, since the other part -a + b is shown zero as per (1).
Similarly second inequality can be proved.
Regards,
Team,
TopperLearning.
Answered by | 12th May, 2010, 07:15: PM
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