quad eq. 3

a > b > c

a -b > 0 > c - b

0 > c - b + a - a  - b + b

0 > (c - 2b + a) - a + b

since b < a

-a + b < 0  .............. (1)

Hence,  in 0 > (c - 2b + a) - a + b,

0 > (c - 2b + a) is true, since the other part -a + b is shown zero as per (1).

Similarly second inequality can be proved.

Regards,

Team,

TopperLearning.