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Proe that SinA-cosA +1/sinA + cosA -1 = 1/secA -tanA

Asked by Simran Kaur 10th September 2013, 1:10 PM
Answered by Expert
Answer:
LHS =
= (1 + sinA) (1 - sinA)/cos A(1 - sinA)
= 1 - sin2A/cos A(1 - sinA)
= cos2A/cos A(1 - sinA)
= cosA/(1 - sinA)
= 1/ (1/cosA - sinA/cosA)
= 1/secA - tanA
= RHS
Answered by Expert 10th September 2013, 3:38 PM
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