Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

probability question.

Asked by 27th May 2008, 9:22 PM
Answered by Expert
Answer:

total no. ways of selecting two no.s = 30 ( to select first no. we have 6 options and to select second no. we have 5 options)

P(X=1) =0   (since any no. which is choosen with 1 will be the largest)

P(X=2) =2*1/30  ( when 1 is selected with 2 )

P(X=3) =2*2/30  ( when 1 or 2 is selected with 3 )

P(X=4) =2*3/30  ( when 1 or 2 or 3 is selected with 4 )

P(X=5)=2*4/30   ( when 1 or 2 or 3 or 4 is selected with 5 )

P(X=6) =2*5/30  ( when 1 or 2 or 3 or 4 or 5 is selected with 6 )

here all probabilities are multiplied by 2 because if (1,2) is a valid pair then (2,1) will also be valid

E(X) = summation of (x*P(x) )

        =(4+12+24+40+60)/30 = 140/30 = 4.67

Answered by Expert 11th September 2008, 12:23 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp