CBSE Class 12-science Answered
P&C
Asked by | 16 Feb, 2010, 11:14: PM
Expert Answer
(c) 1630
We can pick the numbers, one at a time, two.. upto six.
So total number of positive intergers possible 6P1 + 6P2 + 6P3 + 6P4 + 6P5 + 6P6 = 1956
Total number of positive integers starting with zero = 5P1 + 5P2 + 5P3 + 5P4 + 5P5 = 325
Total number of positive integers = 1956 - 325 - 1 = 1630,
(Note that we have subtracted 1, since we don't want 0 to be counted as a positive integer)
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