permutation and combination

Asked by deepak.embedded | 25th Mar, 2010, 10:08: PM

Expert Answer:

The total permutations of all five digits are 5! = 120.

So the arragements to be omitted are,

123**, 12**5, 1*3*5, 1**45,  **345, *234*, 1234*, *2345, 1*345, .....

And these corresponds to 2 arrangements each, therefore total 6x2 + 5 + 1 = 18

Hence the required number of arrangments = 120 - 18 = 102

Regards,

Team,

TopperLearning.

Answered by  | 2nd Apr, 2010, 07:02: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.