Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

permutation and combination
Asked by deepak.embedded | 25 Mar, 2010, 10:08: PM
Expert Answer

The total permutations of all five digits are 5! = 120.

So the arragements to be omitted are,

123**, 12**5, 1*3*5, 1**45,  **345, *234*, 1234*, *2345, 1*345, .....

And these corresponds to 2 arrangements each, therefore total 6x2 + 5 + 1 = 18

Hence the required number of arrangments = 120 - 18 = 102

Regards,

Team,

TopperLearning.

Answered by | 02 Apr, 2010, 07:02: AM
CBSE 12-science - Maths
Asked by | 10 Apr, 2010, 01:53: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by | 02 Apr, 2010, 11:47: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by deepak.embedded | 25 Mar, 2010, 10:08: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by deepak.embedded | 25 Mar, 2010, 10:06: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by | 25 Mar, 2010, 09:29: AM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by | 23 Mar, 2010, 01:48: AM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by raghs321 | 14 Mar, 2010, 11:18: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by | 12 Mar, 2010, 07:30: AM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by | 12 Mar, 2010, 07:22: AM
ANSWERED BY EXPERT
CBSE 12-science - Maths
P&C
Asked by | 16 Feb, 2010, 11:14: PM
ANSWERED BY EXPERT
Season Break Offer!
Get 60% Flat off instantly.
Avail Now
×