Probability
Asked by | 2nd Apr, 2010, 11:47: PM
Expert Answer:
P(AUB)= 0.6
P(AB) = 0.2
P(AUB)=P(A)+P(B)-P(AB)
0.8 =P(A)+P(B)
P(A¯)+P( B¯) = 2-P(A)+P(B)
P(A¯)+P( B¯)=2-0.8 =1.2
Answered by | 3rd Apr, 2010, 09:52: AM
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