Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739
For Business Enquiry

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

please sove the following question:
 

Asked by manasd 24th January 2017, 9:24 PM
Answered by Expert
Answer:
begin mathsize 16px style The space equation space of space the space curve space is space straight y equals fraction numerator left parenthesis straight x minus 7 right parenthesis over denominator left parenthesis straight x minus 2 right parenthesis left parenthesis straight x minus 3 right parenthesis end fraction rightwards double arrow straight y left parenthesis straight x minus 2 right parenthesis left parenthesis straight x minus 3 right parenthesis equals straight x minus 7
So comma space straight y left parenthesis straight x minus 2 right parenthesis left parenthesis straight x minus 3 right parenthesis minus straight x plus 7 equals 0
This space cuts space the space straight x minus axis space at space the space point comma space where space straight y equals 0. space Putting space straight y equals 0 space in space left parenthesis straight i right parenthesis comma space we space get
minus straight x plus 7 equals 0 rightwards double arrow straight x equals 7
So comma space the space point space of space contact space is space left parenthesis 7 comma 0 right parenthesis.
Differentiating space left parenthesis straight i right parenthesis space wrt space straight x comma space we space get
dy over dx left parenthesis straight x minus 2 right parenthesis left parenthesis straight x minus 3 right parenthesis plus straight y left parenthesis 2 straight x minus 5 right parenthesis minus 1 equals 0
Putting space straight x equals 7 space and space straight y equals 0 space in space left parenthesis ii right parenthesis space comma space we space get
open parentheses dy over dx close parentheses subscript left parenthesis 7 comma 0 right parenthesis end subscript left parenthesis 7 minus 2 right parenthesis left parenthesis 7 minus 3 right parenthesis plus 0 left parenthesis 2 left parenthesis 7 right parenthesis minus 5 right parenthesis minus 1 equals 0
rightwards double arrow open parentheses dy over dx close parentheses subscript left parenthesis 7 comma 0 right parenthesis end subscript left parenthesis 7 minus 2 right parenthesis left parenthesis 7 minus 3 right parenthesis minus 1 equals 0 rightwards double arrow open parentheses dy over dx close parentheses subscript left parenthesis 7 comma 0 right parenthesis end subscript equals 1 over 20
So comma space the space equation space of space the space tangent space at space left parenthesis 7 comma 0 right parenthesis space is space straight y minus 0 equals open parentheses dy over dx close parentheses subscript left parenthesis 7 comma 0 right parenthesis end subscript left parenthesis straight x minus 7 right parenthesis
rightwards double arrow straight y equals 0 equals 1 over 20 left parenthesis straight x minus 7 right parenthesis rightwards double arrow straight x minus 20 straight y minus 7 equals 0
The space equation space of space the space normal space at space left parenthesis 7 comma 0 right parenthesis space is space straight y minus 0 equals negative 1 over open parentheses dy over dx close parentheses subscript left parenthesis 7 comma 0 right parenthesis end subscript left parenthesis straight x minus 7 right parenthesis
rightwards double arrow straight y minus 0 equals negative 20 left parenthesis straight x minus 7 right parenthesis
rightwards double arrow 20 straight x plus straight y minus 140 equals 0 end style
Answered by Expert 25th January 2017, 9:59 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp