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Please solve

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Asked by brijk456 3rd September 2019, 12:06 AM
Answered by Expert
Answer:
Given:
 
Mass of water = 4 kg
 
                     = 4000 gm
 
Freezing point of water = 0°C
 
ΔTf = 0− (−6 )
 
      = 6 °C
 
Molar mass of ethylene glycol (C2H6O2) = 62
 
We know,
 
straight M subscript 2 space equals space fraction numerator straight K subscript straight f cross times straight W subscript 2 cross times 1000 over denominator increment straight T subscript straight f cross times straight W subscript 1 end fraction
space space space space space
62 space space equals space fraction numerator 1.85 space cross times straight W subscript 2 cross times 1000 over denominator 6 cross times space 4000 end fraction

space straight W subscript 2 space equals 804.32 space gm
 
Mass of ethylene glycol is 804.32 g
Answered by Expert 3rd September 2019, 1:44 PM
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