1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

# Please Sir/Ma'am answer my question quickly as my Board Exams is on 2nd march,2013. "Ram & Shyam are friends.What is the probability that both will have(i)different birthdays? (ii)same birthday?(ignoring a leap year)"

Asked by MANISHA MOHANTY 25th February 2013, 9:03 AM
There are 365 days in a year and so, total number of outcomes possible are 365.
However, for them to have different birthdays i.e. if Ram has his birthday on a given date, then Shyam can have his birthday on any of the remaining 364 days except that day. So, the favourable outcomes for Shyam are 364 but for Ram, all of the 365 days are possible.

P(different birthdays) = P(Ram's birthday) * P(Shaym's birthday)
P(different birthdays) = 365/365 * 364/365 = 364/365

P(same birthdays) = 1 - P(different birthdays)
P(same birthdays) = 1- 364/365
P(same birthdays) = 1/365
Answered by Expert 25th February 2013, 6:35 PM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10