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Asked by miaowmira1900 15th February 2020, 8:33 PM
power delivered by left side AC voltage source = vm im cosφ

where φ is phase difference between current and voltage

im = vm / z  , where z is impedence = ( 452 + 22 ) ≈ 45 Ω

Phase difference φ = tan-1(-45/2) = -87.5o

Since left side source voltage already has a phase 50o , actual phase difference = (50 - 87.5) = -37.5o

Hence power delivered by left side AC voltage source = 10 × ( 10/45) cos(-37.5) ≈ 1.763 W

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Similarly power delivered by right side AC voltage source = vm im cosφ

where φ is phase difference between current and voltage

im = vm / Z  , where z is impedence = ( 1002 + 22 ) ≈ 100 Ω

Phase difference φ = tan-1(100/2) = 89o

Hence power delivered by right side AC voltage source = 10 × ( 10/45) cos(89) ≈ 0.04 W

Hence total power delivered to passive element 2Ω resistance = ( 1.763+ 0.04 ) W = 1.80 W

Answered by Expert 18th February 2020, 9:44 AM
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