NEET Class neet Answered
physics doubts
Asked by sakshid777 | 25 Jan, 2024, 11:37: AM
Expert Answer
Displacement for particle 1 is,
x1 = A.sin(wt) ...(1)
Displacement for particle 2 is,
x2 = A.sin(wt+y) ...(2)
Given that: x1=x2=A/2 ... (3)
From (1) and (3)
A/2 = A.sin(wt)
Solving this we get,
wt=π/6 or wt=5π/6
Putting these values in (2), we get,
sin(π/6) = A sin(5π/6+y) = A/2
Solving this we get,
y = -2π/3
Thus, the phase difference between the 2 particles is 2π/3.
The negative sign indicates that particles are moving in opposite sides.
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