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two simple pendulum of length 1m and 16 m length .if both starts its oscillation from mean position .they will be in same phsse after shorter pendulum completed n oscillation then find value of n

Asked by ashutosharnold1998 | 13 May, 2020, 11:27: AM

Expert Answer

L e t space n subscript 1 space a n d space T subscript 1 space b e space o s c i l l a t i o n s space a n d space t i m e space p e r i o d space o f space s h o r t e r space p e n d u l u m space a n d space space n subscript 2 space a n d space T subscript 2 space b e space o s c i l l a t i o n s space a n d space t i m e space p e r i o d space o f space l o n g e r space p e n d u l u m space T i m e space p e r i o d space o f space p e n d u l u m space i s space g i v e n space a s comma space T space equals space 2 pi square root of calligraphic l over g end root space T h u s comma space T space proportional to space square root of calligraphic l space A n d space T subscript 1 space cross times n subscript 1 space equals space T subscript 2 space cross times n subscript 2 space end subscript space calligraphic l subscript 1 space b e space l e n g t h space o f space s h o r t e r space p e n d u l u m space calligraphic l subscript 2 space o f space l o n g e r space p e n d u l u m space n subscript 1 over n subscript 2 space equals space T subscript 2 over T subscript 1 space equals space square root of calligraphic l subscript 2 over calligraphic l subscript 1 end root space equals space square root of 16 over 1 end root space equals space 4 over 1 space T h u s comma space n subscript 1 equals space 4 n subscript 2 space T h u s comma space w h e n space s h o r t e r space p e n d u l u m space c o m p l e t e s space 4 space o s c i l l a t i o n s space t h e space l o n g e r space p e n d u l u m space w i l l space c o m p l e t e space 1 space o s c i l l a t i o n W i t h space t h i s space t h e y space w i l l space b e space i n space s a m e space p h a s e. space n space equals 4

Answered by Shiwani Sawant | 13 May, 2020, 13:52: PM

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