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NEET Class neet Answered

two simple pendulum of length 1m and 16 m length .if both starts its oscillation from mean position .they will be in same phsse after shorter pendulum completed n oscillation then find value of n
Asked by ashutosharnold1998 | 13 May, 2020, 11:27: AM
answered-by-expert Expert Answer
L e t space n subscript 1 space a n d space T subscript 1 space b e space o s c i l l a t i o n s space a n d space t i m e space p e r i o d space o f space s h o r t e r space p e n d u l u m space
a n d space space n subscript 2 space a n d space T subscript 2 space b e space o s c i l l a t i o n s space a n d space t i m e space p e r i o d space o f space l o n g e r space p e n d u l u m space
T i m e space p e r i o d space o f space p e n d u l u m space i s space g i v e n space a s comma space

T space equals space 2 pi square root of calligraphic l over g end root space
T h u s comma space
T space proportional to space square root of calligraphic l space

A n d space
T subscript 1 space cross times n subscript 1 space equals space T subscript 2 space cross times n subscript 2 space end subscript space
calligraphic l subscript 1 space b e space l e n g t h space o f space s h o r t e r space p e n d u l u m space
calligraphic l subscript 2 space o f space l o n g e r space p e n d u l u m space
n subscript 1 over n subscript 2 space equals space T subscript 2 over T subscript 1 space equals space square root of calligraphic l subscript 2 over calligraphic l subscript 1 end root space equals space square root of 16 over 1 end root space equals space 4 over 1 space

T h u s comma space
n subscript 1 equals space 4 n subscript 2 space

T h u s comma space
w h e n space s h o r t e r space p e n d u l u m space c o m p l e t e s space 4 space o s c i l l a t i o n s space t h e space l o n g e r space p e n d u l u m space w i l l space c o m p l e t e space 1 space o s c i l l a t i o n
W i t h space t h i s space t h e y space w i l l space b e space i n space s a m e space p h a s e. space
n space equals 4
Answered by Shiwani Sawant | 13 May, 2020, 01:52: PM
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