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Asked by parthasarkar9801 | 17 Nov, 2023, 07:47: AM
answered-by-expert Expert Answer
 
We assume that the question is as follows as the image resolution is too small:
 
A 1.00 x 10–20 kg particle is vibrating with simple harmonic motion with a period of 1.00 x 10–5 s and a maximum speed of 1.00 x 103 m/s. 
The maximum displacement of the particle is 
(1) 1.59 mm  
(2) 1.00 m  
(3) 10 m  
(4) None of these
 
Solution: 
v subscript m a x end subscript space equals space a omega v subscript m a x end subscript space equals a space fraction numerator 2 pi over denominator T end fraction space rightwards double arrow a equals space fraction numerator v subscript m a x end subscript space cross times space T over denominator a cross times 2 pi end fraction rightwards double arrow a space equals space fraction numerator 1 space cross times 10 cubed cross times 1.00 space x space 10 to the power of negative 5 end exponent over denominator 2 pi end fraction space equals space 1.59 space m m
 
 
Answered by Shiwani Sawant | 17 Nov, 2023, 11:43: AM
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