1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

022-62211530

Mon to Sat - 11 AM to 8 PM

# one of the satellites of jupiter , has an orbital period of 1.769 days and the radius of the orbit

Asked by 12th September 2009, 2:15 AM

The time period is, T = 2πR/V,

T2 = 4π2R2/V2 ............(1)

The centripetal force for the satellite's motion is the gravitational force between satellite and Jupiter,

mV2/R = GMm/R2, where m is the mass of the satellite and M is the mass of Jupiter and other symbols have their usual meaning.

V2 = GM/R

Using this V2 in (1),

T2 = 4π2R3/(GM)

M = 4π2R3/(GT2)

M = (4)(3.14)2(4.22x108)3/((6.67x10-11)(1.769x24x3600)2)

= 1.90 x 1027 kg

= 2x1027 kg

Sun's Mass is, 2x1030 kg.

Hence the Jupiter's mass is 1000th that of sun.

Regards,

Team,

TopperLearning.

Answered by Expert 4th November 2009, 2:23 PM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10