CBSE Class 11-science Answered
Pls reply soon with explaining it !!!Pls
Asked by nidhilmohan | 14 Jan, 2010, 05:36: AM
Expert Answer
Dear Student
F1 = (m2/ a2 )
F2=(m2/ a2 )
F= F1 cos30 + F2 cos 30o = (m2/ a2 ) 2cos30
Distance of the particle from the centre of the triangle =R
R cos 30 =a/2 ==> R =a/ (2cos30)
If the particles continuous to rotate in circle ==> centripetal force balanced by F
therefore F= mV2/ R =mV2 X2cos30/ a
mV2 X2cos30/ a =(m2/ a2 ) 2cos30 ==>V= 
m / a
Regards
Topperlearning
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