Pls reply soon with explaining it !!!Pls

Dear Student

 F1 = (m²/ a² ) 

F2=(m²/ a² ) 

F= F1 cos30 + F2 cos 30^{o =} (m²/ a² )  2cos30

Distance of the particle from the centre of the triangle =R

R cos 30 =a/2  ==>     R  =a/ (2cos30)

If the particles continuous to rotate in circle  ==> centripetal force balanced by F

therefore F= mV²/ R =mV² X2cos30/ a

mV² X2cos30/ a   =(m²/ a² )  2cos30    ==>V= m   /   a

Regards

Topperlearning