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N2 +3H2=2NH3

In the above reaction,what is the equivalent weight of NH3 and H2 and N2?

Asked by pb_ckt 19th May 2019, 11:59 PM
Answered by Expert
Answer:
In formation of ammonia-
 
 
N subscript 2 plus 3 H subscript 2 space space end subscript rightwards arrow 2 NH subscript 3
Oxidation state of N in N =0
 Oxidation state of N in NH3   =-3
 
change in oxidation number of N  in Nin formation of NH=3
For 2 N atom = 6
 
So equivalent weight of N2 =28/6=14/3  g(molecular weight of N2 =28 g)
 
Equivalent weight of NH3= 17/3  g  (molecular weight of NH3 =17 g)
 
 
Oxidation number change in H is =1 ( from 0 to +1)
         so for two H atom in H =2
 
It means, equivalent weight of H2 = 2/1=2 g
Answered by Expert 20th May 2019, 11:30 AM
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