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ICSE Class 10 Answered

Law of area of cross section's second part.
Asked by aryavyas6840.10sdatl | 21 Apr, 2020, 02:44: PM
answered-by-expert Expert Answer
The resistance of a wire depends on the following factors:
 i.Directly proportional tothelength (lof the wire 
ii.Inversely proportional tothearea ofcross-section ofthewire
iii.Nature of the material of the wire
 
So according to the above factors, 

R proportional to 1 over A space a n d space R proportional to calligraphic l

w h e r e comma
R space minus space r e s i s tan c e space o f space w i r e space
A space minus space A r e a space o f space c r o s s space s e c t i o n space o f space w i r e space

A space equals space pi r squared space
rightwards double arrow R proportional to fraction numerator calligraphic l over denominator pi r squared space end fraction
therefore R equals rho fraction numerator calligraphic l over denominator pi r squared space end fraction

w h e r e comma space
rho space minus space p r o p o r t i o n a l i t y space c o n s tan t space k n o w n space a s space r e s i s t i v i t y space o f space w i r e space 
Answered by Shiwani Sawant | 21 Apr, 2020, 04:20: PM
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