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a current of 4 amp flows in a wire of resistance 60 2. calculate: (a) power dissipated in the wire. (b) potential difference across the wire. (c) electrical energy consumed in 2 minutes.
Asked by ashrafali8060 | 04 May, 2021, 18:53: PM
answered-by-expert Expert Answer
I = 4 A 
R = 60 Ω
Potential difference across wire, 
V = IR = 4 x 60 = 240 V 
Power dissipated, 
P = VI = 240 x 4 = 960 W 
 
Thus, electrical energy consumed in 2 minutes, 
E = P x t = 960 x 2 x 60  = 115200 J = 115.2 kJ 
Answered by Shiwani Sawant | 04 May, 2021, 19:42: PM

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