a current of 4 amp flows in a wire of resistance 60 2. calculate: (a) power dissipated in the wire. (b) potential difference across the wire. (c) electrical energy consumed in 2 minutes.

Asked by ashrafali8060 | 4th May, 2021, 06:53: PM

Expert Answer:

I = 4 A 
R = 60 Ω
Potential difference across wire, 
V = IR = 4 x 60 = 240 V 
Power dissipated, 
P = VI = 240 x 4 = 960 W 
 
Thus, electrical energy consumed in 2 minutes, 
E = P x t = 960 x 2 x 60  = 115200 J = 115.2 kJ 

Answered by Shiwani Sawant | 4th May, 2021, 07:42: PM