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CBSE Class 11-science Answered

in chemistry laboratory 10 %by mass of sulphuric acid is used. if the density of the solution is 1.8g /cm cube. then find the molality
Asked by shaileshbhagat82816 | 05 Jul, 2018, 07:24: AM
answered-by-expert Expert Answer
Given space colon Molar space mass space of space straight H subscript 2 SO subscript 4 space equals space 98 straight g divided by mole space equals space Mm Density space left parenthesis straight d right parenthesis space equals space 1.8 straight g divided by cc straight W divided by straight w space equals space 10 percent sign Volume space straight V space equals space 1 space dm cubed space equals space 1 space straight L space equals space 1000 space ml space equals space 1000 cc Mass space of space the space solution space equals space straight V space cross times space straight D straight M space equals space 1000 space cross times 1.8 space equals space 1800 straight g space per space 1000 cc Using space straight W divided by straight w comma space 10 space percent sign space of space 1800 straight g space of space space straight H subscript 2 SO subscript 4 equals space open parentheses 10 over 100 close parentheses cross times space 1800 space equals 180 space straight g space equals space straight m No. space of space moles space equals space straight m over Mm space equals space 180 over 10 space equals space 18.0 space moles space per space 1000 cc Thus space Molarity space equals space 18 space straight M
Answered by Ramandeep | 05 Jul, 2018, 11:10: AM

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