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ICSE Class 9 Answered

In a parallelogram ABCD, AE=EF=FC. Prove that i. DE is parallel to FB ii. DE=FB iii. DEBF is a parallelogram
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Asked by aryan_sanghvi | 11 Mar, 2018, 12:28: PM
answered-by-expert Expert Answer
begin mathsize 16px style increment DEA space and space increment BFC AD equals BC AE equals FC angle DAE equals angle BCF...... diagonals space bisect so space congruent space by space SAS so space space DE equals FB..... CPCT increment DEC space and space increment BFA DC equals AB AF equals EC DE equals FB so space congruent space by space SSS so space angle DEF equals angle BFE.... CPCT so space alternate space angles space are space equal space so space parallel end style
Answered by Arun | 11 Mar, 2018, 05:30: PM

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