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ICSE Class 9 Answered

In a parallelogram ABCD,AB 20cm and AD 12cm.The bisector of angle A meets  DC at E and BC produced at F.Find the length of CF.
Asked by Lucky | 27 Feb, 2018, 08:59: PM
answered-by-expert Expert Answer

Draw a line TF, parallel to AB, such that T lies on the extended AD, as shown in the figure.
ABFT is also a parallelogram.
Given AF bisects ∠A,
let ∠TAF and ∠BAF =x
As TA || BF,
⇒∠BFA = ∠TAF=x
⇒∠BFA = ∠BAF=x
⇒ΔABF is an isosceles triangle,
⇒BF=AB=20
⇒CF=BF−BC=20−12=8 cm

Answered by Arun | 28 Feb, 2018, 05:44: PM

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