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if cos(a+b)=0 and sin(a-b)=square root 3 /2. find the value of a, b, a+b,a-b

Asked by 22nd July 2012, 10:10 PM
Answered by Expert
Answer:
cos (a + b) = 0 gives a + b = 90 degrees as cos 90 = 0
sin (a - b) = sqrt 3/2 gives a - b = 60 as sin 60 degrees = sqrt 3/2
Add the two equations, to get,
2a = 150 
a = 75
So, b = 90 - 75 = 15
Answered by Expert 22nd July 2012, 10:13 PM
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