CBSE Class 12-science Answered

how to solve all this?

Asked by Ibrahim Mohammed | 11 Dec, 2015, 01:55: PM

Expert Answer

begin mathsize 11px style Let space the space order space of space reaction space with space respect space to space straight A space and space straight B space be space straight x space and space straight y space respectively. By space using space the space formula comma Rate space equals space straight k space left square bracket straight A right square bracket to the power of straight x space left square bracket straight B right square bracket to the power of straight y Substituting space the space values comma space we space get comma 6.0 space cross times space 10 to the power of negative 3 end exponent space equals space straight k space left square bracket 0.1 right square bracket to the power of straight x space left square bracket 0.1 right square bracket to the power of straight y space space space space space space space space space space space space............ left parenthesis straight i right parenthesis 7.2 space cross times space 10 to the power of negative 2 end exponent space equals space straight k space left square bracket 0.3 right square bracket to the power of straight x space left square bracket 0.2 right square bracket to the power of straight y space space space space space space space space space space space space............ left parenthesis ii right parenthesis 2.88 space cross times space 10 to the power of negative 1 end exponent space equals space straight k space left square bracket 0.3 right square bracket to the power of straight x space left square bracket 0.4 right square bracket to the power of straight y space space space space space space space space space space............ left parenthesis iii right parenthesis 2.40 space cross times space 10 to the power of negative 2 end exponent space equals space space straight k space left square bracket 0.4 right square bracket to the power of straight x space left square bracket 0.1 right square bracket to the power of straight y space space space space space space space space space............ left parenthesis iv right parenthesis Dividing space equation space left parenthesis iv right parenthesis space by space left parenthesis straight i right parenthesis comma space we space get comma fraction numerator 2.40 space cross times space 10 to the power of negative 2 end exponent over denominator 6.0 space cross times space 10 to the power of negative 3 end exponent end fraction space equals space fraction numerator straight k space left square bracket 0.4 right square bracket to the power of straight x space left square bracket 0.1 right square bracket to the power of straight y over denominator straight k space left square bracket 0.1 right square bracket to the power of straight x space left square bracket 0.1 right square bracket to the power of straight y end fraction space space space space space space space space space space space space space space space space space space space space space 4 space equals space left square bracket 4 right square bracket to the power of straight x space space space space space space space space space space space space space space space space space space space space space space straight x space equals space 1 The space order space with space respect space to space straight A space equals space 1 Dividing space equation space left parenthesis iii right parenthesis space by space left parenthesis ii right parenthesis comma space we space get comma fraction numerator 2.88 space cross times space 10 to the power of negative 1 end exponent over denominator 7.2 space cross times space 10 to the power of negative 2 end exponent end fraction space equals space fraction numerator left square bracket 0.3 right square bracket to the power of 1 over denominator left square bracket 0.3 right square bracket to the power of 1 end fraction space cross times space fraction numerator left square bracket 0.4 right square bracket to the power of straight y over denominator left square bracket 0.2 right square bracket to the power of straight y end fraction space space space space space space space space space space space space space space space space space space space space space 4 space equals space left square bracket 2 right square bracket to the power of straight y space space space space space space space space space space space space space space space space space space space space space space straight y space equals space 2 Therefore comma space the space rate space law space is comma space dx over dt space equals space straight k space left square bracket straight A right square bracket space left square bracket straight B right square bracket squared 2.40 space cross times space 10 to the power of negative 2 end exponent space straight M space min to the power of negative 1 space end exponent equals space straight k space left square bracket 0.4 space straight M right square bracket space left square bracket 0.1 space straight M right square bracket squared space space 2.40 space cross times space 10 to the power of negative 2 end exponent space straight M space min to the power of negative 1 space end exponent equals space 0.004 space straight k space straight M cubed space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space straight k space equals space 6.0 space straight M to the power of negative 2 end exponent space min to the power of negative 1 end exponent end style

Answered by Hanisha Vyas | 14 Dec, 2015, 12:39: PM

CBSE Class 12-science Answered

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CBSE Class 12-science Answered

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Calculate rate of reactions

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Integrated Rate Equation

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