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CBSE Class 11-science Answered

From the given compounds which has maximum number of molecules??        (a) 0.1 molar ammonia, (b) 1 gram hydrogen, (c) 40 gram CaCO3,               (d) 6.023×10^20 molecules
Asked by patra04011965 | 27 May, 2019, 08:07: AM
answered-by-expert Expert Answer
We will calculate number of molecules in easch case.
left parenthesis straight a right parenthesis space 0.1 space mole space NH subscript 3 space space 1 space mole space of space NH subscript 3 space have equals space 6.023 cross times 10 to the power of 23 space molecules space space 0.1 space mole space of space NH subscript 3 space will space have equals space 6.023 cross times 10 to the power of 23 cross times 0.1 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 6.023 cross times 10 to the power of 22 space molecules left parenthesis straight b right parenthesis space 1 space straight g space straight H subscript 2 space space space Number space of space moles equals 1 half space space space 1 space mole space of space straight H subscript 2 space end subscript space have equals space 6.023 cross times 10 to the power of 23 space molecules space space space space space space space 1 half space mole space of space straight H subscript 2 space will space have equals 1 half cross times space 6.023 cross times 10 to the power of 23 space molecules space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space left parenthesis straight c right parenthesis space 40 space straight g space CaCO subscript 3 Number space of space moles equals 40 over 100 equals 0.4 space moles 1 space mole space of space CaCO subscript 3 space have equals space 6.023 cross times 10 to the power of 23 space molecules 0.4 space mole space of space CaCO subscript 3 space have equals 6.023 cross times 10 to the power of 23 cross times 0.4 space molecules left parenthesis straight d right parenthesis 6.023 cross times cross times 10 to the power of 23 space molecules space left parenthesis already space given right parenthesis space space
As you can see number of molecules is highest in 1 g H2.  So correct answer is (b).
Answered by Ravi | 27 May, 2019, 11:44: AM

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