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find the hcf of 81 and 237 and express it as a linear combination of 81 and 237 
Asked by rajani.vinod | 02 Jun, 2019, 03:41: PM
answered-by-expert Expert Answer
By Euclid's Division Algorithm,
237=81(2)+(75).....(1)
81=75(1) + (6).....(2)
75=6(12)+(3).....(3)
6=3(2)+(0)
HCF =3
Expressing it in the form of 237x+81y=HCF
3=75-6(12).......from(3)
3=75-(81-75)(12)......from(2)
3=75-(81×12-75×12)
3=75-81×12+75×12
3=75(13)-81(12)
3=(237-81×2)(13)-81(12).....from(1)
3=237(13)-81(38)
3=237(13)+81(-38)
Therefore, x =13 , y =- 38
Answered by Arun | 02 Jun, 2019, 08:43: PM

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