Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
For Business Enquiry


Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number


Mon to Sat - 11 AM to 8 PM

Find the equation of the parabola with vertex [2,-3] and focus [0,5]

Asked by arkabanerjee 29th January 2011, 9:05 PM
Answered by Expert
Dear student,
Let A(2, -3) be the vertex and F(0, 5) be the focus.
Let the axis meet the directrix at a point Z(α,β).
Then, A is the mid point of ZF.
So, 2 = α+0/2
and, -3=β+5/2
Thus, the coordinates of Z are (4, -11).
Now, slope of ZF = 5+11/0-4=-4
So, slope of the directrix = 1/4
Thus, the directrix is a line passing through the point (4, -11) and has a slope equal to 1/4.
Thus, the equation of the directrix is given by:
Let P (x, y) be any point on the parabola. Then,
PF = length of the perpendicular from P on x-4y-48=0
Simplify this expression to get the required equation of the parabola.
We hope that this clarifies your query.
Answered by Expert 7th February 2011, 9:46 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp