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CBSE Class 9 Answered

Find four solutions of the following linear equation in two variables. 2 (x + 3) -3 (y - 1) = 0
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
answered-by-expert Expert Answer

2 (x + 3) -3 (y - 1) = 0

2x + 6 - 3y + 3 = 0

2x - 3y = -9

Solutions can be calculated as below:

(i) When x = 0, we have:

-3y = -9

y = 3

(x, y) = (0, 3)

(ii) When y = 0, we have:

2x = -9

x = -4.5

(x, y) = (-4.5, 0)

(iii) When y = 1, we have:

2x - 3 = -9

2x = -6

x = -3

(x, y) = (-3, 1)

(iv) When y = -1, we have:

2x - (-3) = -9

2x + 3 = -9

2x = -12

x = -6

(x, y) = (-6, -1)

The four solutions of the given equation are (0, 3), (-4.5, 0), (-3, 1), (-6, -1).

Answered by | 04 Jun, 2014, 03:23: PM
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