CBSE Class 9 Answered
Find four solutions of the following linear
equation in two variables.
2 (x + 3) -3 (y - 1) = 0
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
2 (x + 3) -3 (y - 1) = 0
2x + 6 - 3y + 3 = 0
2x - 3y = -9
Solutions can be calculated as below:
(i) When x = 0, we have:
-3y = -9
y = 3
(x, y) = (0, 3)
(ii) When y = 0, we have:
2x = -9
x = -4.5
(x, y) = (-4.5, 0)
(iii) When y = 1, we have:
2x - 3 = -9
2x = -6
x = -3
(x, y) = (-3, 1)
(iv) When y = -1, we have:
2x - (-3) = -9
2x + 3 = -9
2x = -12
x = -6
(x, y) = (-6, -1)
The four solutions of the given equation are (0, 3), (-4.5, 0), (-3, 1), (-6, -1).
Answered by | 04 Jun, 2014, 03:23: PM
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