7. A number consists of two digits whose sum is 12. If 18 is added to the number, the digits are
reversed. Find the number.
Asked by Mn2790976
| 19th May, 2022,
09:45: AM
Let the digit at the tens place be x and the digit at the unit place be y.
x+y=12 .........(1)
Required Number = (10x+y).
Number obtained on reversing the digits = (10y+x).
According to the condition, we get
(10y+x)−(10x+y)=18
→ 9y−9x=18
→ y−x=2 ..........(2)
Adding (1) and (2), we get
2y=14 →y=7
→ x= 12 - 7 = 5
Hence, the required number is 57.
Let the digit at the tens place be x and the digit at the unit place be y.
x+y=12 .........(1)
Required Number = (10x+y).
Number obtained on reversing the digits = (10y+x).
According to the condition, we get
(10y+x)−(10x+y)=18
→ 9y−9x=18
→ y−x=2 ..........(2)
Adding (1) and (2), we get
2y=14 →y=7
→ x= 12 - 7 = 5
Hence, the required number is 57.
Answered by Renu Varma
| 19th May, 2022,
04:14: PM
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