CBSE Class 10 Answered
Express HCF of 45 and 27 in the form 27x + 45y.
Asked by aakashdev10 | 03 Mar, 2019, 01:25: PM
Expert Answer
45 = 27 x 1 + 18
27 = 18 x 1 + 9
18 = 9 x 2 + 0
HCF = 9
9 = 27x + 45y
9 = 27 - 18 x 1
9 = 27 - 18 x 1
18 = 45 - 27 x 1
9 = 27 - [ 45 x 27 x 1 ] x 1= 27 x 2 - 45
9 = 27 x 2 + 45 x [ -1 ]
x = 2
y = -1
Answered by Arun | 03 Mar, 2019, 08:03: PM
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