1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

022-62211530

Mon to Sat - 11 AM to 8 PM

During a football match, the ball shot towards the goal struck the defender's foot at the speed of 10m/s and it bounced back at 20m/s. if the time of impact was 0.2 sec, and mass of the ball 1/2 kg, then the average force exerted by defender on the ball???

Asked by SYOHAN 26th July 2012, 5:20 PM
Let us assume that the ball bounced back in the direction exactly opposite to what it had came.
mass of ball, m= 0.5 kg
Intial momentum: p1 = 0.5 x 10 = 5 kgm/s
final momentum: p2 = 0.5 x (-20) = 10 kgm/s (negative sign due to opposite direction of motion)
Thus change in momentum, p = p2-p1 = -15 kgm/s
Rate of change of momentum, t = 0.2 s
Thus force exerted on ball = p/t = -75 N
Answered by Expert 26th July 2012, 10:44 PM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10

RELATED STUDY RESOURCES :

Latest Questions

Gujarat X Social Studies
Asked by kingsk60581 16th July 2019, 12:08 AM
NEET NEET Physics
Asked by Jigarvora18 15th July 2019, 11:56 PM