CBSE Class 10 Answered
current of 1 A is drawn by a filament of an electric bulb.Number of electrns passing through a cross section of the filament in 16 secs wouyld be
1. 1020
2. 1016
3. 1018
4. 1023
Asked by gpnkumar0 | 04 Feb, 2018, 09:48: PM
Expert Answer
Charge = current × time = 1 A x 16 s = 16 C
charge of electron = 1.6 x 10-19 C
hence no. of electrons = 16/(1.6x 10-19 ) = 1020
Answered by Thiyagarajan K | 05 Feb, 2018, 11:22: AM
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