Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739
For Business Enquiry

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

conic sections

Asked by gazalbhatnagar 20th February 2009, 7:18 PM
Answered by Expert
Answer:

let eqn is x2 + y2 +2gx + 2fy + c =0   it passes through (4,1) so we have  8g + 2f + c + 17 = 0 .....(1)

passes through (6,5)  so we have  12g + 10 f + c + 61 = 0.........(2)

center (-g , -f ) on the line 4x + y = 16  ===>  4g + f = -16..........(3)

solving we get  g = -3 , f = -4 , c  = 15  and eqn as  x2 + y2 - 6x - 8 y +15 = 0

Answered by Expert 20th February 2009, 7:34 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp