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Asked by sahare | 10 Feb, 2010, 06:01: PM Expert Answer

Dear Student

a=4i+j+3k ,   b=i+3j+2k  and  c=2i+7k

ab= sqrt [ (4-1)^2+(1-3)^2+(3-2)^2]= sqrt 14

bc=sqrt [ (1-2)^2+(3-0)^2+(2-7)^2]=sqrt  35

ac=sqrt [ (4-2)^2+(1-0)^2+(3-7)^2] =sqrt 21

here  bc^2=35

ab^2 =14

ac^2=21

bc^2= ab^2 +ac^2

this is the Pythogous theorem for right angle triangle

So abc is a right angle triangle

Regards

Team Topperlearningf

Answered by | 12 Feb, 2010, 02:00: PM
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