CBSE Class 11-science Answered

Calculate the number of sulphate ions in 100mL of 0.001M H2SO4 solution. . Concentration of glucose in blood is approximately 90 mg / 100 ml. Find the molarity of glucose solution in blood .

Asked by tps.mjmdr | 29 May, 2018, 08:07: PM

Expert Answer

1 right parenthesis space T h e space a n s w e r space o f space t h e space f i r s t space q u e s t i o n colon space space space space space space space space space space space space space space space space space H C l space rightwards arrow with blank on top space H to the power of plus space plus space C l to the power of minus I t space i s space o b s e r v e d space t h a t space 1 space m o l e space o f space H C l space d i s s o c i a t e s space t o space g i v e space 1 space m o l e space o f space C l to the power of minus M space equals fraction numerator left parenthesis n space cross times space 1000 right parenthesis over denominator V end fraction therefore space n space equals space fraction numerator left parenthesis 0.001 space cross times space 100 right parenthesis over denominator 1000 end fraction space equals space 0.0001 space m o l e s S i n c e comma space n u m b e r space o f space m o l e s space o f space H C l space equals space n o. space o f space C l to the power of minus T h e r e f o r e comma space n o. space o f space C l to the power of minus space equals space 0.0001 space m o l e 1 space m o l e space o f space C l to the power of minus comma space c o n t a i n s space 6.023 space cross times space 10 to the power of 23 space c h l o r i d e space i o n s N o w comma space 0.0001 m o l e space o f space C l to the power of minus comma space w i l l space c o n t a i n space left parenthesis 6.023 space cross times 10 to the power of 23 space cross times space 0.0001 right parenthesis space equals space 6.023 space cross times space 10 to the power of 19 space c h l o r i d e space i o n s.

M a s s space o f space C subscript 6 H subscript 12 O subscript 6 space equals space 180 space a m u space G i v e n space equals space 90 space m g space equals space 0.090 space g comma space 100 space m l space equals space 0.100 space L 0.100 space L space 0.090 space g space space C subscript 6 H subscript 12 O subscript 6 space cross times fraction numerator 1 space m o l e space C subscript 6 H subscript 12 O subscript 6 over denominator 180.2 space g space C subscript 6 H subscript 12 O subscript 6 end fraction space equals space 0.00050 space M o l space C subscript 6 H subscript 12 O subscript 6 space m o l a r i t y space equals space fraction numerator 0.00050 space m o l over denominator 0.100 space L end fraction space equals space 0.0050 space M space equals space 5.0 space cross times space 10 to the power of negative 3 end exponent M

Answered by Ramandeep | 30 May, 2018, 10:45: AM

CBSE Class 11-science Answered

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CBSE Class 11-science Answered

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