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boron occurs in nature in form of two isotopes having atomic masses 10 and 11.what are the percentage abundances of these isotopes in a sample boron having averag atomic mass 10.8.please explain.

Asked by Akash Sundi 26th December 2011, 10:39 AM
Answered by Expert
Answer:

The percent abundance can be calculated by using the formula:

Average atomic weight of the element =  (exact weight of isotope 1) X (abundance of isotope 1) + (exact weight of isotope 2) X (abundance of isotope 2)

Let the abundance of B-10 be assigned 'x' and the B-11 be '1 - x.'

So, (x) (10) + (1 - x) (11) = 10.8

10x + 11 - 11x = 10.8

x = 0.2

1 - x = 0.8

So, the percent abundance of B-10 is 20% and of B-11 is 80%.

 

Answered by Expert 26th December 2011, 11:12 AM
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