CBSE Class 10 Answered
Part (a)
A1 = A3 = 1 A
i.e., Ammeter reading A1 and A3 are equal .
Ammeter reading A1 shows the current enters the resitors network and
Ammeter reading A3 shows the current exits the resitors network .
Both currents are one and the same.
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Part (b)
A2 = (1/4) A3
A3 is total current drawn from battery that equals 1 A .
Total current 1 A passes through 4 equal resistors that are connected parallel .
Hence current divides equally through each resistor .
Hence ammeter reading A2 = (1/4) A3
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Part (c)
V1 = 1.5 V
V1 is voltage across two 3Ω resistors that are connected parallel .
Equivalent resitance the resistors is 1.5Ω .
Since 1 A is passing through these resistors , we get 1.5 V across these resistors.
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Part (d)
Total resitance = 1.5Ω + 1 Ω + 0.75 Ω = 3.25 Ω
two parallel resistors each of resistance 3Ω gives equivalenet resistance 1.5 Ω .
three parallel resistors each of resistance 3Ω gives equivalenet resistance 1.0 Ω .
four parallel resistors each of resistance 3Ω gives equivalenet resistance 0.75 Ω .