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Asked by pankajchahal2580 | 16 Jan, 2023, 19:23: PM
Qn.(6)
Equivalenet resistance 1Ω is less than all three given resistances 6Ω , 3Ω and 2Ω .
Hence all resistors should be connected in parallel.
If R1 , R2 , R3 are connected parallel , then equivalenet resistance is given as
![begin mathsize 14px style R subscript e q end subscript space equals space fraction numerator R subscript 1 space R subscript 2 space R subscript 3 over denominator R subscript 1 space R subscript 2 space plus space R subscript 2 R subscript 3 plus R subscript 3 R subscript 1 end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/a60de430336b1c18d4db20b7ca44b399.png)
Using above expression, we get equivalenet resistance of 6Ω , 3Ω and 2Ω connected in parallel as
![begin mathsize 14px style R subscript e q end subscript space equals space fraction numerator 6 space cross times 3 space cross times 2 over denominator left parenthesis space 6 space cross times space 3 space right parenthesis space plus space left parenthesis 3 cross times 2 right parenthesis plus left parenthesis 2 cross times 6 right parenthesis end fraction space equals space 1 space capital omega end style](https://images.topperlearning.com/topper/tinymce/cache/522d9f74cbe4293ec87ff1e5daa7f2ee.png)
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Qn. (8)
![](https://images.topperlearning.com/topper/tinymce/imagemanager/files/178eed610bfb1fab6412b1f4effd7f7463c56258aa6e19.95132220f4.png)
Object is placed at left side of lens between main focus point F and optical center O .
Image is formed at same side where object is placed.
Image is virtual , magnified and erect.
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