NEET Class neet Answered
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Asked by jhajuhi19 | 26 Jul, 2021, 07:31: PM
Expert Answer
2 V and 4V battery are connected in parallel , but positive polarity of 2 V is connected to negative polarity of 4 V .
Hence there is a current flow in the loop due to sum of EMFs of batteries and the magnitude of current is decided by sum of inetrnal resistances of batteries.
current I = (4+2) V / (1+1) Ω = 3 A
By knowing the current, if we determine Potential difference Vxy between X and Y , we get
Vxy = - 4 + ( 3 × 1 ) = -1 V
Actually Vxy is terminal voltage of either 4V or 2V battery when they are connected in parallel.
If we try to calculate the terminal voltage of 2V battery we get , Vxy = 2 -(3 × 1 ) = -1 V
Hence the given circuit becomes as shown below
Potential difference across A and B , VAB = ( -1 +3 ) V = 2 V
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