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NEET Class neet Answered

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Asked by pankajpankaj55224 | 16 Jun, 2022, 04:37: PM
answered-by-expert Expert Answer
Power dissipated in resistor = i2 R
 
where i is the current passing through resistor of resistance R
 
if 36 W is dissipated in 9 Ω resistor , then current i through resistor is calculated as follows
 
i2 × 9 = 36 
 
hence we get current i = begin mathsize 14px style square root of 36 divided by 9 end root end style A = 2 A
Voltage across 9 Ω resistor = i × R = 2 × 9 = 18 V
 
Since 6 Ω resistor is in parallel to 9 Ω resistor , voltage across 6 Ω resistor also 18 V
 
Hence current through 6 Ω resistor = voltage / resistance = (18 / 6 ) A = 3 A
 
Hence current drawn from battery = ( 3 + 2 ) A = 5 A
 
Voltage across 2 Ω resistor = i × R = 5 × 2 = 10 V
Answered by Thiyagarajan K | 16 Jun, 2022, 08:36: PM
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